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3.1x^2+1.8x-0.9=0
a = 3.1; b = 1.8; c = -0.9;
Δ = b2-4ac
Δ = 1.82-4·3.1·(-0.9)
Δ = 14.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.8)-\sqrt{14.4}}{2*3.1}=\frac{-1.8-\sqrt{14.4}}{6.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.8)+\sqrt{14.4}}{2*3.1}=\frac{-1.8+\sqrt{14.4}}{6.2} $
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